x^2=(64x)/4

Solution for x^2=(64x)/4 equation:

x^2=(64x)/4

We move all terms to the left:

x^2-((64x)/4)=0

We add all the numbers together, and all the variables

x^2-(+64x/4)=0

We get rid of parentheses

x^2-64x/4=0

We multiply all the terms by the denominator


x^2*4-64x=0

Wy multiply elements

4x^2-64x=0

a = 4; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·4·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*4}=\frac{128}{8}
=16
$